Advertisements
Advertisements
प्रश्न
(3x - 5)(2x + 7) = 0
Advertisements
उत्तर
(3x - 5)(2x + 7) = 0
2x + 7 = 0 or 3x - 5 = 0
x = `-(7)/(2) or x = (5)/(3)`
Hence x = `(5)/(3) and x = - (7)/(2)` are two roots of the equation.
संबंधित प्रश्न
Find the values of k for which the roots are real and equal in each of the following equation:
(3k+1)x2 + 2(k + 1)x + k = 0
Solve the following quadratic equation using formula method only
3x2 + 12 = 32 x
Solve the following quadratic equation using formula method only
3a2x2 +8abx + 4b2 = 0, a ≠ 0
Find the value of m for which the equation (m + 4)x2 + (m + 1)x + 1 = 0 has real and equal roots.
`sqrt(3)x^2 + 10x + 7sqrt(3)` = 0
If `sqrt(2)` is a root of the equation `"k"x^2 + sqrt(2x) - 4` = 0, find the value of k.
If b2 – 4ac > 0 and b2 – 4ac < 0, then write the nature of roots of the quadratic equation for each given case
The probability of selecting integers a ∈ [–5, 30] such that x2 + 2(a + 4)x – 5a + 64 > 0, for all x ∈ R, is ______.
Complete the following activity to determine the nature of the roots of the quadratic equation x2 + 2x – 9 = 0 :
Solution :
Compare x2 + 2x – 9 = 0 with ax2 + bx + c = 0
a = 1, b = 2, c = `square`
∴ b2 – 4ac = (2)2 – 4 × `square` × `square`
Δ = 4 + `square` = 40
∴ b2 – 4ac > 0
∴ The roots of the equation are real and unequal.
If one root of the quadratic equation x2 + 12x – k = 0 is thrice the other root, then find the value of k.
