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प्रश्न
–3 is a zero of y2 + y – 6
पर्याय
True
False
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उत्तर
This statement is True.
Explanation:
Zero of y2 + y – 6 is given by,
y2 + y – 6 = 0
⇒ y2 + 3x – 2x – 6 = 0
⇒ y(y + 3) – 2(x + 3) = 0
⇒ (y – 2)(y + 3) = 0
⇒ y = 2 or –3
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संबंधित प्रश्न
Find p(0), p(1) and p(2) for the following polynomial:-
p(y) = y2 – y + 1
Verify whether the following zeroes of the polynomial, indicated against them.
`p(x) = 3x + 1, x = -1/3`
Verify whether the following zeroes of the polynomial, indicated against them.
p(x) = x2 – 1, x = 1, –1
If `x = −1/2` is a zero of the polynomial `p(x)=8x^3-ax^2 -+2` find the value of a.
Find the zero of the polynomial of the following:
p(x) = ax when a ≠ 0
Find the zero of the polynomial in the following:
h(x) = ax + b, a ≠ 0, a, b ∈ R
Verify whether the following are zeros of the polynomial, indicated against them, or not
p(x) = (x + 3) (x – 4), x = −3, x = 4
Find the zeroes of the polynomial in the following:
p(x) = x – 4
Find the zeroes of the polynomial:
p(x) = (x – 2)2 – (x + 2)2
If a, b, c are all non-zero and a + b + c = 0, prove that `a^2/(bc) + b^2/(ca) + c^2/(ab) = 3`.
