Question

22^nd term of the A.P. : `3/2, 1/2, (-1)/2, (-3)/2, ...` is:

पर्याय

• `45/2`

• –9

• `(-39)/2`

• –21

Answer 1

`bb((-39)/2)`

Explanation:

Given, `3/2, 1/2, (-1)/2, (-3)/2, ...`

Here, a = `3/2`, d = `1/2 - 3/2 = -1`

T₂₂ = a + (n – 1) d

= `3/2 + (22 - 1)(-1)`

= `3/2 + 21 xx -1`

= `(3 - 42)/2`

= `(-39)/2`