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प्रश्न
20 g of a substance were dissolved in 500 mL of water and the osmotic pressure of the solution was found to be 600 mm of mercury at 15°C. The molecular weight of the substance is ______.
पर्याय
998
1028
1098
1198
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उत्तर
20 g of a substance were dissolved in 500 mL of water and the osmotic pressure of the solution was found to be 600 mm of mercury at 15°C. The molecular weight of the substance is 1198.
Explanation:
To find the molecular weight (M), we use the van't Hoff equation for osmotic pressure:
`pi = (wRT)/(MV)`
Convert Given Units to Standard Form:
Mass (w) = 20 g
Volume (V) = 500 mL = 0.5 L
Osmotic Pressure (π) = `(600 "mm Hg")/(760 "mm Hg/atm")` ≈ 0.7895 atm
Temperature (T) = 15°C + 273.15 = 288.15 K
Gas Constant (R) = 0.0821 L · atm · K−1 · mol−1
Rearranging the formula gives:
`M = (wRT)/(piV)`
`M = (20 xx 0.0821 xx 288.15)/(0.7895 xx 0.5)`
`M ≈ 1198.6` g/mol
