Advertisements
Advertisements
प्रश्न
`((2 tan^2 30^circ sec^2 52^circ sin^2 38^circ)/("cosec"^2 70^circ - tan^2 20^circ))` = ?
पर्याय
2
1
`2/3`
`3/2`
MCQ
Advertisements
उत्तर
`bb(2/3)`
Explanation:
Given expression = `{(2 xx (1/sqrt(3))^2 sec^2 52^circ sin^2 (90^circ - 52^circ))/("cosec"^2 70^circ - tan^2 (90^circ - 70^circ))}`
= `2/3 xx ((sec^2 52^circ cos^2 52^circ)/("cosec"^2 70^circ - cot^2 70^circ))`
= `2/3 xx 1/1`
= `2/3`
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
