Question

1.56 g of sodium peroxide reacts with water according to the following equation:

\[\ce{2Na2O2 + 2H2O -> 4NaOH + O2}\]

Calculate the mass of sodium hydroxide formed.

Answer 1

Mol. Mass of Na₂O₂ = 2 23 + 2 16 = 78 g

Mass of 2Na₂O₂= 156 g

156 g Na₂O₂ gives = 160 g of NaOH

So, 1.56 Na₂O₂ forms NaOH = `160/156 xx 1.56`

= 1.6 g