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प्रश्न
100 g of ice at −10°C is heated on a gas stove till it forms water at 80°C. Calculate:
- Heat energy required to bring the ice to 0°C.
- Heat energy required to melt the ice.
- Heat energy required to bring water to 80°C.
[sp. heat capacity of ice = 2 Jg−1°C−1; sp. heat capacity of water = 4.2 Jg−1°C−1 and sp. latent heat of fusion of ice is 336 Jg−1]
संख्यात्मक
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उत्तर
Given: m = 100 g, cice = 2 Jg−1°C−1, cwater = 4.2 Jg−1°C−1, L = 336 Jg−1
(a) Heat to warm ice from −10°C to 0°C:
Δθ = 0 − (−10) = 10°C
H = mcΔθ
= 100 × 2 × 10
= 2000 J
(b) Heat to melt ice at 0°C:
H = mL
= 100 × 336
= 33600 J
(c) Heat to warm water from 0°C to 80°C:
Δθ = 80 − 0 = 80°C
H = mcΔθ
= 100 × 4.2 × 80
=33600 J
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