Advertisements
Advertisements
प्रश्न
10% of x + 20% of y = 24
3x - y = 20
Advertisements
उत्तर
10% of x + 20% of y = 24
⇒ 0.1x + 0.2y = 24 .....(1) [ On Simplyfying ]
3x - y = 20 .....(2)
Multiply equation (2) by 0.2, We get :
0.6x - 0.2y = 4 ......(3)
Adding equation (3) and (1)
0.6x - 0.2y = 4
+ 01x + 0.2y = 24
0.7x = 28
x = 40
Substituting x = 40 in equation (1), We get
0.1(40) + 0.2y = 24
⇒ 0.2y = 20
⇒ y = 100
∴ Solution is x = 40 and y = 100.
APPEARS IN
संबंधित प्रश्न
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
41x + 53y = 135
53x + 41y = 147
If 2x + y = 23 and 4x - y = 19; find the values of x - 3y and 5y - 2x.
Solve the following pairs of equations:
`(3)/(2x) + (2)/(3y)` = 5
`(5)/x - (3)/y` = 1
Solve the following pairs of equations:
`(3)/x - (1)/y` = -9
`(2)/x + (3)/y` = 5
Solve the following pairs of equations:
`(2)/x + (3)/y = (9)/(xy)`
`(4)/x + (9)/y = (21)/(xy)`
Where x ≠ 0, y ≠ 0
If 2x + y = 23 and 4x - y = 19 : find the value of x - 3y and 5y - 2x.
`4x + 6/y = 15 and 6x - 8/y = 14.` Hence, find a if y = ax - 2.
`(3)/x - (2)/y` = 0 and `(2)/x + (5)/y` = 19, Hence, find a if y = ax + 3.
Can the following equations hold simultaneously?
7y - 3x = 7
5y - 11x = 87
5x + 4y = 43
If yes, find the value of x and y.
A boat goes 18 km upstream in 3 hours and 24 km downstream in 2 hours. Find the speed of the boat in still water and the speed of the stream.
