मराठी

10 g of NaCl solution is mixed with 17 g of silver ni trate solution . Calculate the weight of silver chloride precipi tated. AgN03 + NaCl-; AgCI + NaN03

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प्रश्न

10g of NaCl solution is mixed with 17g of silver nitrate solution. Calculate the weight of silver chloride precipitated.
AgNO3 + NaCl → AgCI + NaNO3

बेरीज
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उत्तर

Given reaction is :
AgNO3 + NaCl → AgCl + NaNO3
Molecular mass of AgNO3 is 170
Molecular mass of AgCI is 143.5
170g of AgNO3 produces = 143.5g of AgCl
17g of AgNO3 will produce = 143.5 x 17/170 = 14.35g
So, the weight of silver chloride precipitated is 14.35g

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Mole Concept and Stoichiometry - Exercise 2 [पृष्ठ ११६]

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फ्रँक Chemistry Part 2 [English] Class 10 ICSE
पाठ 5 Mole Concept and Stoichiometry
Exercise 2 | Q 15 | पृष्ठ ११६

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