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Tamil Nadu Board of Secondary EducationHSC Arts कक्षा ११

HSC Arts कक्षा ११ - Tamil Nadu Board of Secondary Education Question Bank Solutions

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In the set Z of integers, define mRn if m − n is divisible by 7. Prove that R is an equivalence relation

[1] Sets, Relations and Functions
Chapter: [1] Sets, Relations and Functions
Concept: undefined >> undefined

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The relation R defined on a set A = {0, −1, 1, 2} by xRy if |x2 + y2| ≤ 2, then which one of the following is true?

[1] Sets, Relations and Functions
Chapter: [1] Sets, Relations and Functions
Concept: undefined >> undefined

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Let R be the set of all real numbers. Consider the following subsets of the plane R × R: S = {(x, y) : y = x + 1 and 0 < x < 2} and T = {(x, y) : x − y is an integer} Then which of the following is true?

[1] Sets, Relations and Functions
Chapter: [1] Sets, Relations and Functions
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The number of relations on a set containing 3 elements is

[1] Sets, Relations and Functions
Chapter: [1] Sets, Relations and Functions
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Let R be the universal relation on a set X with more than one element. Then R is

[1] Sets, Relations and Functions
Chapter: [1] Sets, Relations and Functions
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Let X = {1, 2, 3, 4} and R = {(1, 1), (1, 2), (1, 3), (2, 2), (3, 3), (2, 1), (3, 1), (1, 4), (4, 1)}. Then R is

[1] Sets, Relations and Functions
Chapter: [1] Sets, Relations and Functions
Concept: undefined >> undefined

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The rule f(x) = x2 is a bijection if the domain and the co-domain are given by

[1] Sets, Relations and Functions
Chapter: [1] Sets, Relations and Functions
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Let f : R → R be defined by f(x) = 1 − |x|. Then the range of f is

[1] Sets, Relations and Functions
Chapter: [1] Sets, Relations and Functions
Concept: undefined >> undefined

Solve for x: |3 − x| < 7

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

Solve for x: |4x − 5| ≥ −2

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

Solve for x: `|3 - 3/4x| ≤ 1/4`

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

Solve for x: |x| − 10 < −3

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

Solve `1/(|2x - 1|) < 6` and express the solution using the interval notation

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

Solve −3|x| + 5 ≤ −2 and graph the solution set in a number line

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

Solve 2|x + 1| − 6 ≤ 7 and graph the solution set in a number line

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

Solve `1/5|10x - 2| < 1`

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

Solve |5x − 12| < −2

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

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If |x + 2| ≤ 9, then x belongs to

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

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If `("k"x)/((x + 2)(x - 1)) = 2/(x + 2) + 1/(x - 1)`, then the value of k is

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined

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If `(1 - 2x)/(3 + 2x - x^2) = "A"/(3 - x) + "B"/(x + 1)`, then the value of A + B is

[2] Basic Algebra
Chapter: [2] Basic Algebra
Concept: undefined >> undefined
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