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Classify the decimal form of the given rational numbers into terminating and non-terminating recurring type.
`11/6`
Concept: undefined >> undefined
Write the following rational number in decimal form.
`127/200`
Concept: undefined >> undefined
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Write the following rational number in `p/q` form
2.514
Concept: undefined >> undefined
Decimal expansion of which of the following is non-terminating recurring?
Concept: undefined >> undefined
The number \[\ce{0.\overset{\bullet}{4}}\] in `p/q` form is ______.
Concept: undefined >> undefined
Write the following number in `p/q` form.
0.555
Concept: undefined >> undefined
Write the following number in `bb("p"/"q")` form.
29.568
Concept: undefined >> undefined
Write the following numbers in `bb("p"/"q")` form.
357.417417...
Concept: undefined >> undefined
Write the following numbers in `bb("p"/"q")` form.
30.219
Concept: undefined >> undefined
Write the following number in its decimal form.
`(-5)/7`
Concept: undefined >> undefined
Write the following number in its decimal form.
`9/11`
Concept: undefined >> undefined
Write the following number in its decimal form.
`sqrt 5`
Concept: undefined >> undefined
Write the following number in its decimal form.
`121/13`
Concept: undefined >> undefined
Write the following number in its decimal form.
`29/8`
Concept: undefined >> undefined
Solve the following equation.
`(x^2 + 12x - 20)/(3x - 5) = (x^2 + 8x + 12)/(2x + 3)`
Concept: undefined >> undefined
Solve the following equation.
`[10x^2 + 15x + 63]/[5x^2 - 25x + 12] = (2x + 3)/( x -5)`
Concept: undefined >> undefined
Solve the following equation.
`[( 2x + 1)^2 + (2x - 1)^2]/[(2x + 1)^2 - (2x - 1)^2] = 17/8`
Concept: undefined >> undefined
Solve the following equation.
`[sqrt( 4x + 1) + sqrt( x + 3 )]/[sqrt( 4x + 1 ) - sqrt( x+3 )]=4/1`
Concept: undefined >> undefined
Solve the following equation.
`[(4x +1)^2 + ( 2x + 3)^2]/[4x^2 + 12x + 9] = 61/36`
Concept: undefined >> undefined
Solve the following equation.
`[(3x - 4)^3 - ( x + 1)^3]/[( 3x - 4)^3 + ( x + 1)^3] = 61/189`
Concept: undefined >> undefined
