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If tan θ + tan 2θ + tan 3θ = tan θ.tan 2θ. tan 3θ, then the general value of the θ is ______.
Concept: undefined >> undefined
Select the correct option from the given alternatives:
In any ΔABC, if acos B = bcos A, then the triangle is
Concept: undefined >> undefined
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Find the principal solutions of the following equation:
sin 2θ = `-1/2`
Concept: undefined >> undefined
Find the principal solutions of the following equation:
tan 3θ = - 1
Concept: undefined >> undefined
Find the principal solutions of the following equation:
cot θ = 0
Concept: undefined >> undefined
Find the general solutions of the following equation:
`tan theta = - sqrt3`
Concept: undefined >> undefined
Find the general solutions of the following equation:
`tan^2 theta = 3`
Concept: undefined >> undefined
Find the general solutions of the following equation:
sin2 θ - cos2 θ = 1
Concept: undefined >> undefined
Find the general solutions of the following equation:
sin θ - cos θ = 1
Concept: undefined >> undefined
In Δ ABC, prove that `cos(("A" - "B")/2) = (("a" + "b")/"c")sin "C"/2` .
Concept: undefined >> undefined
With the usual notations, prove that `(sin("A" - "B"))/(sin ("A" + "B")) = ("a"^2 - "b"^2)/"c"^2`
Concept: undefined >> undefined
In ΔABC, prove that `("a - b")^2 cos^2 "C"/2 + ("a + b")^2 sin^2 "C"/2 = "c"^2`
Concept: undefined >> undefined
In Δ ABC, if cos A = sin B - cos C then show that it is a right-angled triangle.
Concept: undefined >> undefined
If `(sin "A")/(sin "C") = (sin ("A - B"))/(sin ("B - C"))`, then show that a2, b2, c2 are in A.P.
Concept: undefined >> undefined
State whether the following equation has a solution or not?
3 sin θ = 5
Concept: undefined >> undefined
If 2 tan-1(cos x) = tan-1(2 cosec x), then find the value of x.
Concept: undefined >> undefined
If sin-1(1 - x) - 2 sin-1x = `pi/2`, then find the value of x.
Concept: undefined >> undefined
If tan-12x + tan-13x = `pi/4`, then find the value of x.
Concept: undefined >> undefined
Show that `tan^-1 1/2 - tan^-1 1/4 = tan^-1 2/9`.
Concept: undefined >> undefined
Show that `cot^-1 1/3 - tan^-1 1/3 = cot^-1 3/4`.
Concept: undefined >> undefined
