Please select a subject first
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For annuity due,
C = ₹ 20,000, n = 3, I = 0.1, (1.1)–3 = 0.7513
Therefore, P = `square/0.1 xx [1 - (1 + 0.1)^square]`
= 2,00,000 [1 – 0.7513]
= ₹ `square`
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The future amount, A = ₹ 10,00,000
Period, n = 20, r = 5%, (1.025)20 = 1.675
A = `"C"/"I" [(1 + "i")^"n" - 1]`
I = `5/200` = `square` as interest is calculated semi-annually
A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`
10,00,000 = `"C"/0.025 [(1 + 0.025)^square - 1]`
= `"C"/0.025 [1.675 - 1]`
10,00,000 = `("C" xx 0.675)/0.025`
C = ₹ `square`
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Which of the following can’t be a component of a time series?
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Which component of time series refers to erratic time series movements that follow no recognizable or regular pattern?
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Choose the correct alternative:
The following trend line equation was developed for annual sales from 1984 to 1990 with 1984 as base or zero year.
Y = 500 + 60X (in 1000 ₹). The estimated sales for 1984 (in 1000 ₹) is
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Choose the correct alternative:
An overall upward or downward pattern in an annual time series would be contained in which component of the times series?
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______ components of time series is indicated by a smooth line
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______ component of time series is indicated by periodic variation year after year.
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State whether the following statement is True or False:
Seasonal variation can be observed over several years
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Cyclical variation can occur several times in a year.
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Choose the correct alternative:
The Cost of Living Index Number by Aggregate Expenditure Method is same as
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The Cost of Living Index Number by Aggregate Expenditure Method is given by ______
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Calculate the Cost of Living Index Number for the following data.
| Group | Base Year | Current Year | |
| Price | Quantity | Price | |
| Food | 40 | 5 | 20 |
| Clothing | 30 | 10 | 35 |
| Fuel and Lighting | 20 | 17 | 10 |
| House Rent | 60 | 22 | 10 |
| Miscellaneous | 70 | 25 | 8 |
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Given the following table, find the Cost of living Index Number using Aggregate Expenditure Method by completing the activity.
| Group | p0 | q0 | p1 | p0q0 | p1q0 |
| A | 23 | 4 | 25 | `square` | 100 |
| B | 15 | 5 | 20 | 75 | `square` |
| C | 5 | 9 | 8 | `square` | 72 |
| D | 12 | 5 | 18 | 60 | `square` |
| E | 8 | 6 | 13 | `square` | 78 |
| Total | – | – | – | 320 | `square` |
Therefore, Cost of Living Index using Aggregate Expenditure method is
CLI = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx square`
= `square/square xx 100`
= `square`
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Choose the correct alternative:
The cost matrix of an unbalanced assignment problem is not a ______
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An unbalanced assignment problems can be balanced by adding dummy rows or columns with ______ cost
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A ______ assignment problem does not allow some worker(s) to be assign to some job(s)
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State whether the following statement is True or False:
To convert the assignment problem into maximization problem, the smallest element in the matrix is to deducted from all other elements
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Find the assignments of salesman to various district which will yield maximum profit
| Salesman | District | |||
| 1 | 2 | 3 | 4 | |
| A | 16 | 10 | 12 | 11 |
| B | 12 | 13 | 15 | 15 |
| C | 15 | 15 | 11 | 14 |
| D | 13 | 14 | 14 | 15 |
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For the following assignment problem minimize total man hours:
| Subordinates | Required hours for task | |||
| I | II | III | IV | |
| A | 7 | 25 | 26 | 10 |
| B | 12 | 27 | 3 | 25 |
| C | 37 | 18 | 17 | 14 |
| D | 18 | 25 | 23 | 9 |
Subtract the `square` element of each `square` from every element of that `square`
| Subordinates | Required hours for task | |||
| I | II | III | IV | |
| A | 0 | 18 | 19 | 3 |
| B | 9 | 24 | 0 | 22 |
| C | 23 | 4 | 3 | 0 |
| D | 9 | 16 | 14 | 0 |
Subtract the smallest element in each column from `square` of that column.
| Subordinates | Required hours for task | |||
| I | II | III | IV | |
| A | `square` | `square` | 19 | `square` |
| B | `square` | `square` | 0 | `square` |
| C | `square` | `square` | 3 | `square` |
| D | `square` | `square` | 14 | `square` |
The lines covering all zeros is `square` to the order of matrix `square`
The assignment is made as follows:
| Subordinates | Required hours for task | |||
| I | II | III | IV | |
| A | 0 | 14 | 19 | 3 |
| B | 9 | 20 | 0 | 22 |
| C | 23 | 0 | 3 | 0 |
| D | 9 | 12 | 14 | 0 |
Optimum solution is shown as follows:
A → `square, square` → III, C → `square, square` → IV
Minimum hours required is `square` hours
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