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HSC Commerce (English Medium) १२ वीं कक्षा - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

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Mathematics and Statistics
< prev  1061 to 1080 of 1916  next > 

Use quantifiers to convert the given open sentence defined on N into a true statement.

3x – 4 < 9

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Use quantifiers to convert the given open sentence defined on N into a true statement.

Y + 4 > 6

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

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Choose the correct alternative:

If y = (x )x + (10)x, then `("d"y)/("d"x)` = ?

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If xy = 2x – y, then `("d"y)/("d"x)` = ______

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If y = `"a"^((1 + log"x"))`, then `("d"y)/("d"x)` is ______

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If u = 5x and v = log x, then `("du")/("dv")` is ______

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If u = ex and v = loge x, then `("du")/("dv")` is ______

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

State whether the following statement is True or False:

If y = log(log x), then `("d"y)/("d"x)` = logx

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

State whether the following statement is True or False:

If y = 4x, then `("d"y)/("d"x)` = 4x  

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if y = [log(log(logx))]2 

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `(dy)/(dx)`, if xy = yx 

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if xy = log(xy)

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if x = `sqrt(1 + "u"^2)`, y = log(1 +u2)

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If x = t.logt, y = tt, then show that `("d"y)/("d"x)` = tt 

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if y = (log x)x + (x)logx

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if y = xx + (7x – 1)x 

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if y = `x^(x^x)`

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if y = `root(3)(((3x - 1))/((2x + 3)(5 - x)^2)`

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If xa .yb = `(x + y)^((a + b))`, then show that `("d"y)/("d"x) = y/x`

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if y = x(x) + 20(x) 

Solution: Let y = x(x) + 20(x) 

Let u = `x^square` and v = `square^x`

∴ y = u + v

Diff. w.r.to x, we get

`("d"y)/("d"x) = square/("d"x) + "dv"/square`   .....(i)

Now, u = xx

Taking log on both sides, we get

log u = x × log x

Diff. w.r.to x,

`1/"u"*"du"/("d"x) = x xx 1/square + log x xx square`

∴ `"du"/("d"x)` = u(1 + log x)

∴ `"du"/("d"x) = x^x (1 +  square)`    .....(ii)

Now, v = 20x

Diff.w.r.to x, we get

`"dv"/("d"x") = 20^square*log(20)`     .....(iii)

Substituting equations (ii) and (iii) in equation (i), we get

`("d"y)/("d"x)` = xx(1 + log x) + 20x.log(20)

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined
< prev  1061 to 1080 of 1916  next > 
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