Please select a subject first
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State whether the following statement is true or false.
If f'(x) > 0 for all x ∈ (a, b) then f(x) is decreasing function in the interval (a, b).
Concept: undefined >> undefined
y2 = (x + c)3 is the general solution of the differential equation ______.
Concept: undefined >> undefined
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Write the converse, inverse, and contrapositive of the statement. "If 2 + 5 = 10, then 4 + 10 = 20."
Concept: undefined >> undefined
Solve the following LP.P.
Maximize z = 13x + 9y,
Subject to 3x + 2y ≤ 12,
x + y ≥ 4,
x ≥ 0,
y ≥ 0.
Concept: undefined >> undefined
Conditional of p → q is equivalent to p → ∼ q.
Concept: undefined >> undefined
If f(x) = `x - 1/x`, x∈R, x ≠ 0 then f(x) is increasing.
Concept: undefined >> undefined
`int 1/(a^2 - x^2) dx = 1/(2a) xx` ______.
Concept: undefined >> undefined
The optimal value of the objective function is attained at the ______ of feasible region.
Concept: undefined >> undefined
`int (f^'(x))/(f(x))dx` = ______ + c.
Concept: undefined >> undefined
`int(7x - 2)^2dx = (7x -2)^3/21 + c`
Concept: undefined >> undefined
Find the value of x for which the function f(x)= 2x3 – 9x2 + 12x + 2 is decreasing.
Given f(x) = 2x3 – 9x2 + 12x + 2
∴ f'(x) = `squarex^2 - square + square`
∴ f'(x) = `6(x - 1)(square)`
Now f'(x) < 0
∴ 6(x – 1)(x – 2) < 0
Since ab < 0 ⇔a < 0 and b < 0 or a > 0 and b < 0
Case 1: (x – 1) < 0 and (x – 2) < 0
∴ x < `square` and x > `square`
Which is contradiction
Case 2: x – 1 and x – 2 < 0
∴ x > `square` and x < `square`
1 < `square` < 2
f(x) is decreasing if and only if x ∈ `square`
Concept: undefined >> undefined
The set of feasible solutions of LPP is a ______.
Concept: undefined >> undefined
If bxy < 0 and byx < 0 then 'r ' is ______.
Concept: undefined >> undefined
Solution which satisfy all constraints is called ______ solution.
Concept: undefined >> undefined
A function f is said to be increasing at a point c if ______.
Concept: undefined >> undefined
The degree of the differential equation `((d^2y)/dx^2)^2 + (dy/dx)^3` = ax is 3.
Concept: undefined >> undefined
Converse of the statement q `rightarrow` p is ______.
Concept: undefined >> undefined
`int(1 - x)^(-2)` dx = `(1 - x)^(-1) + c`
Concept: undefined >> undefined
Evaluate `int(1 + x + x^2/(2!) )dx`
Concept: undefined >> undefined
Evaluated the following
`int x^3/ sqrt (1 + x^4 )dx`
Concept: undefined >> undefined
