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Arts (English Medium) कक्षा १२ - CBSE Question Bank Solutions for Mathematics

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Mathematics
< prev  1901 to 1920 of 9028  next > 

Let S = {abc} and T = {1, 2, 3}. Find F−1 of the following functions F from S to T, if it exists.

F = {(a, 2), (b, 1), (c, 1)}

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = {−1, 0, 1, 2}, B = {−4, −2, 0, 2} and f, g : A → B be functions defined by f(x) = x2 − x, x ∈ A and g(x) = `2|x - 1/2|- 1`, x ∈ A. Are f and g equal?

Justify your answer. (Hint: One may note that two functions f : A → B and g : A → B such that f(a) = g(a) ∀ a ∈ A are called equal functions.)

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

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Let fR → R be the Signum Function defined as

f(x) = `{(1,x>0), (0, x =0),(-1, x< 0):}`

and gR → be the Greatest Integer Function given by g(x) = [x], where [x] is greatest integer less than or equal to x. Then does fog and gof coincide in (0, 1]?

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Prove the following:

3 sin−1 x = sin−1 (3x − 4x3), `x ∈ [-1/2, 1/2]`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Prove the following: 

3cos−1x = cos−1(4x3 − 3x), `x ∈ [1/2, 1]`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Prove `tan^(-1)  2/11 + tan^(-1)  7/24 = tan^(-1)  1/2`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Prove `2 tan^(-1)  1/2 + tan^(-1)  1/7 = tan^(-1)  31/17`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Write the following function in the simplest form:

`tan^(-1)  (sqrt(1+x^2) -1)/x`, x ≠ 0

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Write the function in the simplest form: `tan^(-1)  1/(sqrt(x^2 - 1)), |x| > 1`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Write the following function in the simplest form:

`tan^(-1) (sqrt((1-cos x)/(1 + cos x)))`, 0 < x < π

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Write the function in the simplest form:  `tan^(-1)  ((cos x - sin x)/(cos x + sin x)) `,` 0 < x < pi`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Write the following function in the simplest form:

`tan^(-1)  x/(sqrt(a^2 - x^2))`, |x| < a

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Write the following function in the simplest form:

`tan^(-1) ((3a^2 x - x^3)/(a^3 - 3ax^2)), a > 0; (-a)/sqrt3 < x < a/sqrt3`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Find the value of the following:

`tan^-1 [2 cos (2  sin^-1  1/2)]`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Find the value of `cot(tan^(-1) a + cot^(-1) a)`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Find the value of the following:

`tan  1/2 [sin^(-1)  (2x)/(1+ x^2) + cos^(-1)  (1-y^2)/(1+y^2)]`, |x| < 1, y > 0 and xy < 1

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

if `sin(sin^(-1)  1/5 + cos^(-1) x)  = 1` then find the value of x

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

if `tan^(-1)  (x-1)/(x - 2) + tan^(-1)  (x + 1)/(x + 2) = pi/4` then find the value of x.

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Find the value of the given expression.

`sin^(-1) (sin  (2pi)/3)`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Find the value of the given expression.

`tan^(-1) (tan  (3pi)/4)`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined
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