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Arts (English Medium) कक्षा १२ - CBSE Question Bank Solutions for Mathematics

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Mathematics
< prev  3441 to 3460 of 4671  next > 

Show that x = 2 is a root of the equation

\[\begin{vmatrix}x & - 6 & - 1 \\ 2 & - 3x & x - 3 \\ - 3 & 2x & x + 2\end{vmatrix} = 0\]  and solve it completely.
 

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

​Solve the following determinant equation:

\[\begin{vmatrix}x + a & b & c \\ a & x + b & c \\ a & b & x + c\end{vmatrix} = 0\]

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

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​Solve the following determinant equation:

\[\begin{vmatrix}x + a & x & x \\ x & x + a & x \\ x & x & x + a\end{vmatrix} = 0, a \neq 0\]

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

​Solve the following determinant equation:

\[\begin{vmatrix}3x - 8 & 3 & 3 \\ 3 & 3x - 8 & 3 \\ 3 & 3 & 3x - 8\end{vmatrix} = 0\]

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

​Solve the following determinant equation:

\[\begin{vmatrix}1 & x & x^2 \\ 1 & a & a^2 \\ 1 & b & b^2\end{vmatrix} = 0, a \neq b\]

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

​Solve the following determinant equation:

\[\begin{vmatrix}x + 1 & 3 & 5 \\ 2 & x + 2 & 5 \\ 2 & 3 & x + 4\end{vmatrix} = 0\]

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

​Solve the following determinant equation:

\[\begin{vmatrix}1 & x & x^3 \\ 1 & b & b^3 \\ 1 & c & c^3\end{vmatrix} = 0, b \neq c\]

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

​Solve the following determinant equation:

\[\begin{vmatrix}1 & 1 & x \\ p + 1 & p + 1 & p + x \\ 3 & x + 1 & x + 2\end{vmatrix} = 0\]
[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined
​Solve the following determinant equation:
\[\begin{vmatrix}15 - 2x & 11 - 3x & 7 - x \\ 11 & 17 & 14 \\ 10 & 16 & 13\end{vmatrix} = 0\]
[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

​Solve the following determinant equation:

\[\begin{vmatrix}3 & - 2 & \sin\left( 3\theta \right) \\ - 7 & 8 & \cos\left( 2\theta \right) \\ - 11 & 14 & 2\end{vmatrix} = 0\]

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined
Show that
`|(x-3,x-4,x-alpha),(x-2,x-3,x-beta),(x-1,x-2,x-gamma)|=0`, where α, β, γ are in A.P.

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If a, b, c are real numbers such that
\[\begin{vmatrix}b + c & c + a & a + b \\ c + a & a + b & b + c \\ a + b & b + c & c + a\end{vmatrix} = 0\] , then show that either
\[a + b + c = 0 \text{ or, } a = b = c\]

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If \[a, b\] and c  are all non-zero and 

\[\begin{vmatrix}1 + a & 1 & 1 \\ 1 & 1 + b & 1 \\ 1 & 1 & 1 + c\end{vmatrix} =\] 0, then prove that 
\[\frac{1}{a} + \frac{1}{b} + \frac{1}{c} +\]1
= 0

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If \[\begin{vmatrix}a & b - y & c - z \\ a - x & b & c - z \\ a - x & b - y & c\end{vmatrix} =\] 0, then using properties of determinants, find the value of  \[\frac{a}{x} + \frac{b}{y} + \frac{c}{z}\]  , where \[x, y, z \neq\] 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Find the area of the triangle with vertice at the point:

(3, 8), (−4, 2) and (5, −1)

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Find the area of the triangle with vertice at the point:

(2, 7), (1, 1) and (10, 8)

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Find the area of the triangle with vertice at the point:

 (−1, −8), (−2, −3) and (3, 2)

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Find the area of the triangle with vertice at the point:

 (0, 0), (6, 0) and (4, 3)

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Using determinants show that the following points are collinear:

(5, 5), (−5, 1) and (10, 7)

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Using determinants show that the following points are collinear:

(1, −1), (2, 1) and (4, 5)

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined
< prev  3441 to 3460 of 4671  next > 
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