हिंदी

Arts (English Medium) कक्षा १२ - CBSE Question Bank Solutions for Mathematics

Advertisements
[object Object]
[object Object]
विषयों
मुख्य विषय
अध्याय
Advertisements
Advertisements
Mathematics
< prev  2101 to 2120 of 9028  next > 

Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = sin2x + cos2x

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Classify the following function as injection, surjection or bijection :

f : Q − {3} → Q, defined by `f (x) = (2x +3)/(x-3)`

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Advertisements

Classify the following function as injection, surjection or bijection :

f : Q → Q, defined by f(x) = x3 + 1

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Classify the following function as injection, surjection or bijection :
f : R → R, defined by f(x) = 5x3 + 4

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = 3 − 4x

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = 1 + x2

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = `x/(x^2 +1)`

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If f : A → B is an injection, such that range of f = {a}, determine the number of elements in A.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Show that the function f : R − {3} → R − {2} given by f(x) = `(x-2)/(x-3)` is a bijection.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = [-1, 1]. Then, discuss whether the following function from A to itself is one-one, onto or bijective : `f (x) = x/2`

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = [-1, 1]. Then, discuss whether the following function from A to itself is one-one, onto or bijective : g(x) = |x|  

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = [-1, 1]. Then, discuss whether the following functions from A to itself is one-one, onto or bijective : h(x) = x2 

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Set of ordered pair of  a function? If so, examine whether the mapping is injective or surjective :{(xy) : x is a person, y is the mother of x}

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Set of ordered pair of a function ? If so, examine whether the mapping is injective or surjective :{(ab) : a is a person, b is an ancestor of a

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A = {1, 2, 3}. Write all one-one from A to itself.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If f : R → R be the function defined by f(x) = 4x3 + 7, show that f is a bijection.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Show that the exponential function f : R → R, given by f(x) = ex, is one-one but not onto. What happens if the co-domain is replaced by`R0^+` (set of all positive real numbers)?

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Show that the logarithmic function  f : R0+ → R   given  by f (x)  loga x ,a> 0   is   a  bijection.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If A = {1, 2, 3}, show that a one-one function f : A → A must be onto.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If A = {1, 2, 3}, show that a onto function f : A → A must be one-one.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined
< prev  2101 to 2120 of 9028  next > 
Advertisements
Advertisements
CBSE Arts (English Medium) कक्षा १२ Question Bank Solutions
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Accountancy
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Business Studies
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Computer Science (Python)
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Economics
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ English Core
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ English Elective - NCERT
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Entrepreneurship
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Geography
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Hindi (Core)
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Hindi (Elective)
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ History
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Informatics Practices
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Mathematics
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Physical Education
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Political Science
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Psychology
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Sanskrit (Core)
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Sanskrit (Elective)
Question Bank Solutions for CBSE Arts (English Medium) कक्षा १२ Sociology
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×