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Science (English Medium) कक्षा ११ - CBSE Question Bank Solutions for Mathematics

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Mathematics
< prev  3901 to 3920 of 5451  next > 

Find the derivative of the following function from first principle.

`1/x^2`

[12] Limits and Derivatives
Chapter: [12] Limits and Derivatives
Concept: undefined >> undefined

Find the derivative of the following function from first principle.

`(x+1)/(x -1)`

[12] Limits and Derivatives
Chapter: [12] Limits and Derivatives
Concept: undefined >> undefined

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Find the derivative of the following function from first principle:

−x

[12] Limits and Derivatives
Chapter: [12] Limits and Derivatives
Concept: undefined >> undefined

Find the derivative of the following function from first principle:

(–x)–1

[12] Limits and Derivatives
Chapter: [12] Limits and Derivatives
Concept: undefined >> undefined

Find the derivative of the following function from first principle: 

sin (x + 1)

[12] Limits and Derivatives
Chapter: [12] Limits and Derivatives
Concept: undefined >> undefined

Find the derivative of the following function from first principle: 

`cos (x - pi/8)`

[12] Limits and Derivatives
Chapter: [12] Limits and Derivatives
Concept: undefined >> undefined

(i) If \[\left( \frac{a}{3} + 1, b - \frac{2}{3} \right) = \left( \frac{5}{3}, \frac{1}{3} \right)\] find the values of a and b

 

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

(ii) If (x + 1, 1) = (3, y − 2), find the values of x and y.

[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

Prove the following identites

sec4x - sec2x = tan4x + tan2x

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\sin^6 x + \cos^6 x = 1 - 3 \sin^2 x \cos^2 x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\left( cosec x - \sin x \right) \left( \sec x - \cos x \right) \left( \tan x + \cot x \right) = 1\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities 
\[cosec x \left( \sec x - 1 \right) - \cot x \left( 1 - \cos x \right) = \tan x - \sin x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\frac{1 - \sin x \cos x}{\cos x \left( \sec x - cosec x \right)} \cdot \frac{\sin^2 x - \cos^2 x}{\sin^3 x + \cos^3 x} = \sin x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identitie

\[\frac{\tan x}{1 - \cot x} + \frac{\cot x}{1 - \tan x} = \left( \sec x cossec x + 1 \right)\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\frac{\sin^3 x + \cos^3 x}{\sin x + \cos x} + \frac{\sin^3 x - \cos^3 x}{\sin x - \cos x} = 2\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\left( \sec x \sec y + \tan x \tan y \right)^2 - \left( \sec x \tan y + \tan x \sec y \right)^2 = 1\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\frac{\cos x}{1 - \sin x} = \frac{1 + \cos x + \sin x}{1 + \cos x - \sin x}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities

\[\frac{\tan^3 x}{1 + \tan^2 x} + \frac{\cot^3 x}{1 + \cot^2 x} = \frac{1 - 2 \sin^2 x \cos^2 x}{\sin x \cos x}\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[1 - \frac{\sin^2 x}{1 + \cot x} - \frac{\cos^2 x}{1 + \tan x} = \sin x \cos x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities

\[\left( \frac{1}{\sec^2 x - \cos^2 x} + \frac{1}{{cosec}^2 x - \sin^2 x} \right) \sin^2 x \cos^2 x = \frac{1 - \sin^2 x \cos^2 x}{2 + \sin^2 x \cos^2 x}\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined
< prev  3901 to 3920 of 5451  next > 
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