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HSC Science (Computer Science) १२ वीं कक्षा - Maharashtra State Board Important Questions for Chemistry

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Chemistry
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An element crystallizes in a f.c.c. lattice with a cell edge of 250 pm. Calculate the density if 300 g of this element contains 2 × 1024 atoms. 

Appears in 3 question papers
Chapter: [1] Solid State
Concept: Calculations Involving Unit Cell Dimensions

An element with molar mass 27 g mol−1 forms a cubic unit cell with edge length 4.05 ✕ 10−8 cm. If its density is 2.7 g cm−3, what is the nature of the cubic unit cell?

Appears in 3 question papers
Chapter: [1] Solid State
Concept: Number of Atoms in a Unit Cell

Define the following term

Schottky defect

Appears in 3 question papers
Chapter: [1] Solid State
Concept: Imperfections in Solids - Introduction

An element with density 2.8 g cm–3 forms a f.c.c. unit cell with edge length 4 x 10–8 cm. Calculate the molar mass of the element.

(Given : NA = 6.022 x 1023 mol –1)

Appears in 3 question papers
Chapter: [1] Solid State
Concept: Calculations Involving Unit Cell Dimensions

Sodium crystallizes in bcc structure. If the edge length of unit cell is 4.3 × 10-8 cm, the radius of Na atom is ______.

Appears in 3 question papers
Chapter: [1] Solid State
Concept: Classification of Crystalline Solids

Sodium crystallizes in bcc structure. If the edge length of unit cell is 4.3 × 10-8 cm, the radius of Na atom is ______.

Appears in 3 question papers
Chapter: [1] Solid State
Concept: Classification of Crystalline Solids

A substance crystallizes in fcc structure. The unit cell edge length is 367.8 pm. Calculate the molar mass of the substance if its density is 21.5 g/cm3.

Appears in 3 question papers
Chapter: [1] Solid State
Concept: Packing Efficiency

Derive the relationship between relative lowering of vapour pressure and molar mass of nonvolatile solute.

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Relative Lowering of Vapour Pressure

Calculate the freezing point of solution when 1.9 g of MgCl2 (M = 95 g mol−1) was dissolved in 50 g of water, assuming MgCl2 undergoes complete ionization.

(Kf for water = 1.86 K kg mol−1)

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Depression of Freezing Point

What happens when the external pressure applied becomes more than the osmotic pressure of solution?

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

What happens when the external pressure applied becomes more than the osmotic pressure of solution?

Appears in 3 question papers
Chapter: [2] Solutions
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

When 2.56 g of sulphur was dissolved in 100 g of CS2, the freezing point lowered by 0.383 K. Calculate the formula of sulphur (Sx).

(Kf for CS2 = 3.83 K kg mol−1, Atomic mass of sulphur = 32 g mol−1]

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Depression of Freezing Point

Blood cells are isotonic with 0.9% sodium chloride solution. What happens if we place blood cells in a solution containing

(i) 1.2% sodium chloride solution?

(ii) 0.4% sodium chloride solution?

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

Blood cells are isotonic with 0.9% sodium chloride solution. What happens if we place blood cells in a solution containing

(i) 1.2% sodium chloride solution?

(ii) 0.4% sodium chloride solution?

Appears in 3 question papers
Chapter: [2] Solutions
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

3.9 g of benzoic acid dissolved in 49 g of benzene shows a depression in freezing point of 1.62 K. Calculate the van't Hoff factor and predict the nature of solute (associated or dissociated).

(Given : Molar mass of benzoic acid = 122 g mol−1, Kf for benzene = 4.9 K kg mol−1)

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Abnormal Molar Masses

Define the following terms : Molarity

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Solubility >> Solubility of a Solid in a Liquid

A solution of glucose (molar mass = 180 g mol–1) in water is labelled as 10% (by mass). What would be the molality and molarity of the solution ? (Density of solution = 1.2 g mL–1)

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass - Introduction

Define Molality.

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Expressing Concentration of Solutions

Define reverse osmosis.

Appears in 3 question papers
Chapter: [2] Solutions and Colligative Properties
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure

Define reverse osmosis.

Appears in 3 question papers
Chapter: [2] Solutions
Concept: Colligative Properties and Determination of Molar Mass >> Osmosis and Osmotic Pressure
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