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प्रश्न
`int(((x^2 + 2)a^((x + tan^-1x)))/(x^2 + 1))dx` is equal to ______
विकल्प
`log(a)a^(x + tan^-1x) + c`
`((x + tan^-1x))/(loga) + c`
`a^(x + tan^-1x)/(loga) + c`
`loga(x + tan^-1`x) + c
MCQ
रिक्त स्थान भरें
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उत्तर
`int(((x^2 + 2)a^((x + tan^-1x)))/(x^2 + 1))dx` is equal to `underline(a^(x + tan^-1x)/(loga) + c)`
Explanation:
Consider, I = `int((x^2 + 2)a^((x + tan^-1x)))/(x^2 + 1)dx`
Let x + tan–1x = t
⇒ `(1 + 1/(1 + x^2))dx` = dt
⇒ `(2 + x^2)/(1 + x^2)dx` = dt
So, I = `int a^t dt`
= `a^t/loga + c`
= `a^(x + tan^-1x)/(loga) + c`
shaalaa.com
Some Special Integrals
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