हिंदी

∫((x2+2)a(x+tan-1x)x2+1)dx is equal to ______

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प्रश्न

`int(((x^2 + 2)a^((x + tan^-1x)))/(x^2 + 1))dx` is equal to  ______ 

विकल्प

  • `log(a)a^(x + tan^-1x) + c`

  • `((x + tan^-1x))/(loga) + c`

  • `a^(x + tan^-1x)/(loga) + c`

  • `loga(x + tan^-1`x) + c

MCQ
रिक्त स्थान भरें
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उत्तर

`int(((x^2 + 2)a^((x + tan^-1x)))/(x^2 + 1))dx` is equal to `underline(a^(x + tan^-1x)/(loga) + c)`

Explanation:

Consider, I = `int((x^2 + 2)a^((x + tan^-1x)))/(x^2 + 1)dx`

Let x + tan–1x = t

⇒ `(1 + 1/(1 + x^2))dx` = dt

⇒ `(2 + x^2)/(1 + x^2)dx` = dt

So, I = `int a^t  dt`

= `a^t/loga + c`

= `a^(x + tan^-1x)/(loga) + c`

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