Question

`x^2-(sqrt3+1)x+sqrt3=0` 

Answer 1

`x^2-(sqrt3+1)x+sqrt3=0` 

⇒`x^2-sqrt3x-x+sqrt3=0` 

⇒`x(x-sqrt3)-1 (x-sqrt3)=0` 

⇒`(x-sqrt3)(x-1)=0` 

⇒`x-sqrt3 or  x-1=0` 

⇒` x= sqrt3  or  x=1` 

Hence, 1 and `sqrt3` are the roots of the given equation.