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प्रश्न

\[\int \left( \sqrt{x} - \frac{1}{\sqrt{x}} \right)^2 dx\]
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उत्तर

\[\int \left( \sqrt{x} - \frac{1}{\sqrt{x}} \right)^2 dx\]
\[ = \int\left( x + \frac{1}{x} - 2 \right)dx\]
` = ∫   x dx + ∫   dx/x - 2\ ∫    x dx`
`= x^2 / 2 + In   | x|  -2 x +C`

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अध्याय 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १४]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.02 | Q 6 | पृष्ठ १४

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