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प्रश्न
Write the relationship between molar solubility (S) and solubility product (Ksp) for CaF2.
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उत्तर
\[\ce{CaF_{2(s)} ⇌ Ca^{2+}_{ (aq)} + 2F^{-}_{ (aq)}}\]
x = 1, y = 2
Ksp = xx yy Sx+y = (1)1 (2)2 S1+2 = 4S3
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