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प्रश्न
Write the reaction to convert propene to isopropyl alcohol.
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उत्तर १
\[\begin{array}{cc}
\ce{\underset{\text{Propene}}{CH3 - CH = CH2} + \underset{\text{(Cold conc.)}}{H2SO4}-> CH3 - CH - CH3 ->[H - OH][\Delta] CH3 - CH - CH3 +}\\
\phantom{..............................}|\phantom{........................}|\\
\phantom{..................................}\ce{\underset{\text{Isopropyl hydrogen sulphate}}{OSO3H}}\phantom{...}\ce{\underset{\text{Propan-2-ol (Isopropyl alcohol)}}{OH}}
\end{array}\]
उत्तर २
\[\begin{array}{cc}
\ce{\underset{\text{Propene}}{CH3 - CH = CH2} + \underset{\text{(Cold conc.)}}{H2SO4}-> CH3 - CH - CH3 ->[H - OH][\Delta] CH3 - CH - CH3 + H2SO4}\\
\phantom{.........................}|\phantom{........................}|\\
\phantom{...........................}\ce{\underset{\text{Isopropyl hydrogen sulphate}}{OSO3H}}\ce{\underset{(Isopropyl alcohol)}{\underset{Propan-2-ol}{OH}}}\end{array}\]
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संबंधित प्रश्न
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\\phantom{...........................}|\\\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}\end{array}\]
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|\phantom{.....}|\phantom{.........}\\
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\ce{CH3}\phantom{....}\\
|\phantom{.......}\\
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|\phantom{.......}\\
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\[\begin{array}{cc}
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3}\\
\phantom{.....}|\phantom{........................}|\phantom{}\\
\phantom{.................}\ce{CH3}\phantom{..............}\ce{CH3 - CH\ - CH2Br}\phantom{}\
\end{array}\]
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dil alkaline \[\ce{KMnO4}\]
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