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प्रश्न
With the help of a ray diagram, show how a compound microscope forms a magnified image of a tiny object, at least distance of distinct vision. Hence derive an expression for the magnification produced by it.
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उत्तर
Image formation by compound microscope at the least distance of distinct vision:

Expression for magnification:
For objective,
Magnification = mo = `"P'Q'"/"PQ" = (-"v")/"u"`
When the image is formed at the least distance of distinct vision, then
Magnification = me = `(1 + "D")/"f"_"e"`
So, final magnification = m = mo × me = `"v"/"u" (1 + "D"/"f"_"e")`
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संबंधित प्रश्न
A compound microscope consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm. How far from the objective should an object be placed in order to obtain the final image at
- the least distance of distinct vision (25 cm), and
- infinity?
What is the magnifying power of the microscope in each case?
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Draw a ray diagram showing image formation in a compound microscope ?
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Draw the labelled ray diagram for the formation of image by a compound microscope.
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An object is placed at a distance u from a simple microscope of focal length f. The angular magnification obtained depends
Draw a labelled ray diagram showing the formation of image by a compound microscope in normal adjustment. Derive the expression for its magnifying power.
A microscope is focussed on a mark on a piece of paper and then a slab of glass of thickness 3 cm and refractive index 1.5 is placed over the mark. How should the microscope be moved to get the mark in focus again?
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- Infinity.
- Least distance of distinct vision (D = 25 cm).
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