Advertisements
Advertisements
प्रश्न
When 5 V potential difference is applied across a wire of length 0.1 m, the drift speed of electrons is 2.5 x 10-4 m/s. If the electron density in the wire is 8 x 1028 m-3, calculate the resistivity of the material of the wire.
Advertisements
उत्तर
The drift speed is
`v_d=I/(`
Now, we know that the current is given from Ohm’s law as
`I=V/R`
`:.v_d = V/`
`:.V/(`
`=>V/(`
Now, resistivity is given as `rho=(RA)/l`
`:.V/(`
`:.rho=5/(8xx10^28xx1.6xx10^(-19)xx2.5xx10^(-4)xx0.1)`
∴ ρ = 1.56 x 10-5 Ωm
APPEARS IN
संबंधित प्रश्न
Why are Si and GaAs preferred materials for solar cells?
Why is potentiometer preferred over a voltmeter for comparison of emf. of cells?
The potential difference between the terminals of a battery of emf 6.0 V and internal resistance 1 Ω drops to 5.8 V when connected across an external resistor. Find the resistance of the external resistor.
In the circuit shown in the figure, ε1 = 3 V, ε2 = 2 V, εa = 1 V and r1 = r2 = r3 = 1Ω. Find the potential difference between the points A and B and the current through each branch.
A voltmeter consists of a 25 Ω coil connected in series with a 575 Ω resistor. The coil takes 10 mA for full-scale deflection. What maximum potential difference can be measured by this voltmeter?
The potential difference across the terminals of a battery of emf 12 V and internal resistance 2 Ω drops to 10 V when it is connected to a silver voltameter. Find the silver deposited at the cathode in half an hour. Atomic weight of silver is 107.9 g mol−1.
A potential difference of 220 V is maintained across 12000 Ω rheostat. Then voltmeter V has a resistance of 6000 Ω and point C is at one fourth the distance from a to b. Then the reading of voltmeter is ______.
In the circuit in figure the potential difference across P and Q will be nearest to
