Question

What will be the mass of carbon dioxide that will contain the same number of molecules as present in 3.2 g of oxygen gas? [At. wt: O = 16, C = 12]

Answer 1

Given: Atomic weight of O = 16

Atomic weight of C = 12

Mass = 3.2 g

Molar mass of O₂ = 16 × 2 = 32 g/mol

Formula: Moles of O₂ = `("Mass of O"_2)/("Molar mass of O"_2)`

= `3.2/32`

= 0.1 mol

Molar mass of CO₂ = 12 + (16 × 2)

= 12 + 32

= 44 g/mol 

Mass = 0.1 × 44

= 4.4 g