Advertisements
Advertisements
प्रश्न
What volume of hydrogen sulphide at STP will burn in oxygen to yield 12.8g suIphurdioxide according to the equation?
2H2S + 3O2 → 2H2O + 2SO2
योग
Advertisements
उत्तर
64g of SO2 will be produced at STP from = 22.4L of H2S
12.8g of SO2 will be produced at STP from= 22.4 x 12.8/64
= 4.48L
So, 4.48L of hydrogen sulphide at STP will burn in oxygen to
yield 12.8g sulphur dioxide.
shaalaa.com
Standard Temperature Pressure (S.T.P.)
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
