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Using `E_"values"^°` of X and Y given below, predict which is better for coating the surface of iron to prevent corrosion and why?
Given:
`E_(X^(2+)//X)^°` = −2.36 V,
`E_(Y^(2+)//Y)^°` = −0.14 V,
`E_(Fe^(2+)//Fe)^°` = −0.44 V
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The oxidation potentials of all elements must be considered, as corrosion involves the oxidation of iron. Iron won’t corrode because an element with a higher oxidation potential than iron will oxidize more quickly than iron.
According to the information provided, the oxidation potential of `E_(Fe^(2+)//Fe)^° = −0.44 V, E_(X^(2+)//X)^° = −2.36 V, and E_(Y^(2+)//Y)^° = −0.14 V`.
`E_(X^(2+)//X)^°` can be utilized to coat the surface of iron since it has a higher oxidation potential than iron.
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2024-2025 (March) Delhi Set 1
