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प्रश्न
Using the following frequency table.
| Marks (obtained out of 10) | 4 | 5 | 7 | 8 | 9 | 10 |
| Frequency | 5 | 10 | 8 | 6 | 12 | 9 |
10 marks the highest frequency.
विकल्प
True
False
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उत्तर
This statement is False.
Explanation:
Frequency of marks 9 = 12
Frequency of marks 10 = 9
∵ 12 > 9
⇒ Frequency of marks 9 > Frequency of marks 10
Therefore, 9 marks has the highest frequency.
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संबंधित प्रश्न
For class interval 20-25 write the lower class limit and the upper class limit.
In the table given below, class-mark and frequencies are given. Construct the frequency table taking inclusive and exclusive classes.
| Class width | Frequency |
| 22 | 6 |
| 24 | 7 |
| 26 | 13 |
| 28 | 4 |
What is the upper class limit for the class 25-35?
What is the class-mark of class 25-35?
If the classes are 0-10, 10-20, 20-30... then in which class should the observation 10 be included?
The value of π up to 50 decimal place is
3.14159265358979323846264338327950288419716939937510
(i) Make a frequency distribution table of digits from 0 to 9 after the decimal place.
(ii) Which are the most and least occurring digits?
A dice was cast 40 times and each score noted is given below. Draw up a frequency table for this data.
3, 2, 5, 6, 4, 2, 3, 1, 6, 6, 2, 3, 5, 3, 5, 3, 4, 2, 4, 5, 4, 2, 6, 3, 3, 2, 4, 3, 3, 4, 1, 4, 3, 3, 2, 2, 5, 3, 3, 4
Inclusive series is a continuous series
Size of the class 150 – 175 is ______.
Complete the following table:
| Weights (in kg.) |
Tally Marks | Frequency (Number of persons) |
| 40 – 50 | `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|` | |
| 50 – 60 | `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|bb|bb|` | |
| 60 – 70 | `\cancel(bb|bb|bb|bb|) bb|` | |
| 70 – 80 | `bb|bb|` | |
| 80 – 90 | `bb|` |
Find the total number of persons whose weights are given in the above table.
