हिंदी

Two solid cylinders, one with diameter 60 cm and height 30 cm and the other with radius 30 cm and height 60 cm, are metled and recasted into a third solid cylinder of height 10 cm.

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प्रश्न

Two solid cylinders, one with diameter 60 cm and height 30 cm and the other with radius 30 cm and height 60 cm, are metled and recasted into a third solid cylinder of height 10 cm. Find the diameter of the cylinder formed.

योग
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उत्तर

For cylinder 1,

Height = h1 = 30 cm

Radius = r1 = `60/2` = 30 cm

Volume = V1

= `pir_1^2h_1`

= π × 30 × 30 × 30

= 27000π cm3

For cylinder 2,

Height = h2 = 60 cm

Radius = r2 = 30 cm

Volume = V

= `pi "r"_2^2 "h"_2`

= π × 30 × 30 × 60

= 54000π cm3

Let r be the radius of the third cylinder.

Height = h = 10 cm

Volume = V

= πr2h

= πr2 × 10

Now,

V = V1 + V

`=>` πr2 × 10 = 27000π + 54000π 

`=>` πr2 × 10 = 81000π

`=>` r2 = 8100

`=>` r = 90

`=>` Diameter = 2r = 180 cm 

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अध्याय 20: Cylinder, Cone and Sphere - Exercise 20 (A) [पृष्ठ २९८]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 20 Cylinder, Cone and Sphere
Exercise 20 (A) | Q 24. | पृष्ठ २९८
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