Question

Two dice are thrown together. The probability of getting the difference of numbers on their upper faces equals to 3 is ______.

विकल्प

• `1/9`

• `2/9`

• `1/6`

• `1/12`

Answer 1

Two dice are thrown together. The probability of getting the difference of numbers on their upper faces equals to 3 is `underlinebb(1/6)`.

Explanation:

When two dice are thrown,

The sample space (S) =

{(1, 1,), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

∴ n(S) = 36

Let A: Event of getting the numbers whose difference is 3.

∴ A = {(1, 4), (2, 5), (3, 6), (4, 1), (5, 2), (6, 3)}

n(A) = 6

∴ Required probability = `(n(A))/(n(S))`

= `6/36`

= `1/6`