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Two Cubes Each of Volume 27 Cm3 Are Joined End to End to Form a Solid. Find the Surface Area of the Resulting Cuboid.

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प्रश्न

Two cubes each of volume 27 cm3 are joined end to end to form a solid. Find the surface area of the resulting cuboid.

योग
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उत्तर

As , volume of a cube = 27 cm3
⇒ (edge)3 = 27

⇒ edge = `root {3}(27)`

⇒ edge = 3 cm
The length of the resulting cuboid , l = 3 + 3 = 6 cm ,
its breath , b = 3 cm and its height , h = 3 cm
Now , the surface area of the resulting cuboid = 2(lb + bh + hl)
= `2  (6 xx 3 + 3 xx 3 + 3 xx 6)`
= 2 (18 + 9 + 18)
= `2 xx 45`
= 90 cm2

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अध्याय 17: Volumes and Surface Areas of Solids - Exercise 19A [पृष्ठ ८७४]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 17 Volumes and Surface Areas of Solids
Exercise 19A | Q 1 | पृष्ठ ८७४

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