Advertisements
Advertisements
प्रश्न
Two cones of same height 6 cm and radii 3 cm and 4 cm are melted and recast into a cylinder of base radius 5 cm. Find the height of the cylinder.
Advertisements
उत्तर
Given:
Two right circular cones, each of height
h = 6 cm
radii r1 = 3 cm
r2 = 4 cm
They are melted and recast into a cylinder with base radius R = 5 cm.
Find the height H of the cylinder.
= `(1/3) π r^2 h` ...[Volume of a cone formula]
= π R2 H ...[Volume of a cylinder]
(Use conservation of volume: total volume of the two cones = volume of the cylinder.)
Compute the volume of the two cones.
Volume of cone 1
= `(1/3) π (3)^2 (6)`
= `(1/3) π × 9 × 6`
= 18π cm3
Volume of cone 2
= `(1/3) π (4)^2 (6)`
= `(1/3) π · 16 · 6`
= 32π cm3
Total volume = 18π + 32π
= 50π cm3
Set it equal to the cylinder volume and solve for H.
Cylinder volume
= π (5)2 H
= 25π H
25π H = 50π
⇒ 25H = 50
⇒ H = 2 cm.
