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प्रश्न
To find out the concentration of SO2 in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below:
| concentration of SO2 (in ppm) | Frequency |
| 0.00 − 0.04 | 4 |
| 0.04 − 0.08 | 9 |
| 0.08 − 0.12 | 9 |
| 0.12 − 0.16 | 2 |
| 0.16 − 0.20 | 4 |
| 0.20 − 0.24 | 2 |
Find the mean concentration of SO2 in the air.
योग
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उत्तर
To find the class marks for each interval, the following relation is used:
`x_i = ("Upper class limit + Lower class limit")/2`
Class size of this data = 0.04
Taking 0.14 as the assumed mean (a), di, ui, fiui are calculated as follows:
|
Concentration of SO2 (in ppm) |
Frequency fi |
Class mark xi |
di = xi − 0.14 | `u_i=(x_i-0.14)/0.04` | fiui |
| 0.00 − 0.04 | 4 | 0.02 | −0.12 | −3 | −12 |
| 0.04 − 0.08 | 9 | 0.06 | −0.08 | −2 | −18 |
| 0.08 − 0.12 | 9 | 0.10 | −0.04 | −1 | −9 |
| 0.12 − 0.16 | 2 | 0.14 | 0 | 0 | 0 |
| 0.16 − 0.20 | 4 | 0.18 | 0.04 | 1 | 4 |
| 0.20 − 0.24 | 2 | 0.22 | 0.08 | 2 | 4 |
| Total | 30 | −31 |
From the table, we obtain
`sumf_i = 30`
`sumf_iu_i = -31`
mean `barx=a+(sumf_iu_i)/(sumf_i)xxh`
`= 0.14 + ((-31)/30)(0.04)`
= 0.14 − 0.04133
= 0.09867
= 0.099 ppm
Therefore, mean concentration of SO2 in the air is 0.099 ppm.
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