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प्रश्न
To a small amount of copper oxide in a beaker, when we add dilute hydrochloric acid slowly with stirring, the change in the colour of the solution is due to the formation of ______.
विकल्प
Copper (II) oxide, which is black in colour.
Copper (I) chloride, which is blue in colour.
Copper (II) chloride, which is blue-green in colour.
Copper (I) oxide, which is black in colour.
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उत्तर
To a small amount of copper oxide in a beaker, when we add dilute hydrochloric acid slowly with stirring, the change in the colour of the solution is due to the formation of copper (II) chloride, which is blue-green in colour.
Explanation:
When black copper (II) oxide reacts with dilute hydrochloric acid, a neutralisation reaction occurs. The copper oxide dissolves to form copper (II) chloride (CuCl2) and water, which imparts a characteristic blue-green colour to the resulting solution.
The chemical equation for this reaction is:
\[\ce{CuO_{(s)} + 2HCl_{(aq)} -> CuCl2_{(aq)} + H2O_{(l)}}\]
