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प्रश्न
Three cubes, whose edges are x cm, 8 cm, and 10 cm respectively, are melted and recast into a single cube of edge 12 cm. Find 'x'.
योग
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उत्तर
Volume of melted single cube x3 + 83 + 103 cm3
= x3 + 512 + 1000 cm3
= x3 + 1512 cm3
Given that 12 cm is edge of the single cube.
123 = x3 + 1512 cm3
x3 = 123 - 1512 cm3
x3 = 1728 - 1512
x3 = 216
x3 = 63
x = 6 cm
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