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प्रश्न
Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarized as follows. Fine the mean heartbeats per minute for these women, choosing a suitable method.
| Number of heartbeats per minute | 65 - 68 | 68 - 71 | 71 - 74 | 74 - 77 | 77 - 80 | 80 - 83 | 83 - 86 |
| Number of women | 2 | 4 | 3 | 8 | 7 | 4 | 2 |
योग
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उत्तर
To find the class mark of each interval (xi), the following relation is used:
`x_i = ("Upper class limit + Lower class limit")/2`
Class size, h, of this data = 3
Taking 75.5 as the assumed mean (a), di, ui, fiui are calculated as follows.
| Number of heart beats per minute |
Number of women fi |
xi | di = xi − 75.5 | `u_i = (x_i-75.5)/3` | fiui |
| 65 − 68 | 2 | 66.5 | − 9 | -3 | -6 |
| 68 − 71 | 4 | 69.5 | − 6 | -2 | -8 |
| 71 − 74 | 3 | 72.5 | − 3 | -1 | -3 |
| 74 − 77 | 8 | 75.5 | 0 | 0 | 0 |
| 77 − 80 | 7 | 78.5 | 3 | 1 | 7 |
| 80 − 83 | 4 | 81.5 | 6 | 2 | 8 |
| 83 − 86 | 2 | 84.5 | 9 | 3 | 6 |
| Total | 30 | 4 |
From the table, we obtain
`sumf_i = 30`
`sumf_iu_i = 4`
mean `barx=a+((sumf_iu_i)/(sumf_i))xxh`
`= 75.5 +(4/30) xx 3`
= 75.5 + 0.4 = 75.9
Therefore, the mean beats per minute for these women are 75.9 beats per minute.
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