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प्रश्न
The total cost function for production and marketing of a product is given by C(x) = `(3x^2)/4 − 7x + 3,` where x is the number of units produced.
Find the level of output (number of units produced) for which MC = AC.
योग
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उत्तर
Total Cost Function: C(x) = `(3x^2)/4 − 7x + 3`
Marginal Cost is the derivative of the Total Cost:
MC = `d/dx [C(x)] = d/dx((3x^2)/4 − 7x + 3)`
MC = `3/4(2x) − 7 = (3x)/2 − 7`
Average Cost is the Total Cost divided by x:
AC = `(C(x))/x = ((3x^2)/4 − 7x + 3)/x`
AC = `(3x)/4 − 7 + 3/x`
Solve for MC = AC
Equate the expressions from Step 1 and Step 2:
`(3x)/2 −7 = (3x)/4 −7 + 3/x` ...[Add 7 to both sides]
`(3x)/2 = (3x)/4 + 3/x`
Multiply the entire equation by 4x to clear the denominators:
`4x ((3x)/2) = 4x((3x)/4) + 4x(3/x)`
6x2 = 3x2 + 12
Subtract 3x2 from both sides:
3x2 = 12
x2 = 4
x = 2
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