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The tangent to the curve y = e2x at the point (0, 1) meets x-axis at ______. - Mathematics

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प्रश्न

The tangent to the curve y = e2x at the point (0, 1) meets x-axis at ______.

विकल्प

  • (0, 1)

  • `(- 1/2, 0)`

  • (2, 0)

  • (0, 2)

MCQ
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उत्तर

The tangent to the curve y = e2x at the point (0, 1) meets x-axis at `(- 1/2, 0)`.

Explanation:

Equation of the curve is y = e2x

Slope of the tangent `"dy"/"dx"` = 2e2x

⇒ `"dy"/"dx"_(0, 1)` = 2 · e0 = 2

∴ Equation of tangent to the curve at (0, 1) is

y –1 = 2(x – 0)

⇒ y – 1 = 2x

⇒ y – 2x = 1

Since the tangent meets x-axis where y = 0

∴ 0 – 2x = 1

⇒ x = `(-1)/2`

So the point is `(- 1/2, 0)`.

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अध्याय 6: Application Of Derivatives - Exercise [पृष्ठ १३९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 6 Application Of Derivatives
Exercise | Q 43 | पृष्ठ १३९

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