Advertisements
Advertisements
प्रश्न
The resale value of a machine decreases over a 10 year period at a rate that depends on the age of the machine. When the machine is x years old, the rate at which its value is changing is ₹ 2200 (x − 10) per year. Express the value of the machine as a function of its age and initial value. If the machine was originally worth ₹1,20,000, how much will it be worth when it is 10 years old?
Advertisements
उत्तर
Let ‘y’ be the value of the machine when machine is ‘x’ years old.
∴ According to the given condition,
`dy/dx = 2200 (x - 10)`
∴ dy = 2200(x – 10) dx
Integrating on both sides, we get
∫1 dy = 2200 ∫ (x-10) dx
∴ `y = 2200 (x^2/2 - 10x) + c`
∴ y = 1100 x2 – 22,000 x + c
when x = 0, y = 1,20,000
∴ 1,20,000 = 1100(0)2 – 22,00(0) + c
∴ c = 1,20,000
∴ The value of the machine can be expressed as a function of it’s age as
y = 1,100x2 – 22,000x + 1,20,000
Initial value: when x = 0, y = 1,20,000
∴ when x = 10,
y = 1100(10)2 – 22,000(10) + 1,20,000
= 10,000
∴ The machine will worth ₹ 10,000 when it is 10 years old.
APPEARS IN
संबंधित प्रश्न
For the differential equation, find the general solution:
`dy/dx + y = 1(y != 1)`
For the differential equation, find the general solution:
y log y dx - x dy = 0
For the differential equation, find the general solution:
`x^5 dy/dx = - y^5`
For the differential equation, find the general solution:
ex tan y dx + (1 – ex) sec2 y dy = 0
For the differential equation find a particular solution satisfying the given condition:
`(x^3 + x^2 + x + 1) dy/dx = 2x^2 + x; y = 1` When x = 0
For the differential equation find a particular solution satisfying the given condition:
`x(x^2 - 1) dy/dx = 1` , y = 0 when x = 2
For the differential equation find a particular solution satisfying the given condition:
`dy/dx` = y tan x; y = 1 when x = 0
For the differential equation `xy(dy)/(dx) = (x + 2)(y + 2)` find the solution curve passing through the point (1, –1).
Find the equation of a curve passing through the point (0, -2) given that at any point (x, y) on the curve, the product of the slope of its tangent and y-coordinate of the point is equal to the x-coordinate of the point.
At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (- 4, -3). Find the equation of the curve given that it passes through (-2, 1).
The volume of spherical balloon being inflated changes at a constant rate. If initially its radius is 3 units and after 3 seconds it is 6 units. Find the radius of balloon after t seconds.
In a bank, principal increases continuously at the rate of r% per year. Find the value of r if Rs 100 doubles itself in 10 years (loge 2 = 0.6931).
Find the equation of the curve passing through the point `(0,pi/4)`, whose differential equation is sin x cos y dx + cos x sin y dy = 0.
Find the particular solution of the differential equation:
`y(1+logx) dx/dy - xlogx = 0`
when y = e2 and x = e
Solve the equation for x:
sin-1x + sin-1(1 - x) = cos-1x, x ≠ 0
Solve the differential equation `"dy"/"dx" = 1 + "x"^2 + "y"^2 +"x"^2"y"^2`, given that y = 1 when x = 0.
Solve the differential equation:
`dy/dx = 1 +x+ y + xy`
Solve
y dx – x dy = −log x dx
Solve
`y log y dx/ dy = log y – x`
Solve: (x + y)(dx – dy) = dx + dy. [Hint: Substitute x + y = z after seperating dx and dy]
The solution of the differential equation, `(dy)/(dx)` = (x – y)2, when y (1) = 1, is ______.
