Question

The reaction of Xe and O₂F₂ gives a Xe compound P. The number of moles of HF produced by the complete hydrolysis of 1 mol of P is ______. (nearest integer)

Answer 1

The reaction of Xe and O₂F₂ gives a Xe compound P. The number of moles of HF produced by the complete hydrolysis of 1 mol of P is 4.

Explanation:

The reaction between Xe and O₂F₂ is:

\[\ce{Xe + 2O2F2 -> XeF4 + 2O2}\]

Thus, compound P = XeF₄ (xenon tetrafluoride).

The hydrolysis of XeF₄ occurs as:

\[\ce{6XeF4 + 12H2O -> 4Xe + 2XeO3 + 24HF + 3O2}\]

From this balanced equation:

6 moles of XeF₄ produce 24 moles of HF.

Calculate HF produced by 1 mole of XeF₄:

\[\ce{\frac{24 mol HF}{6 mol XeF_4}}\] = 4 mol HF per 1 mol XeF₄