Question

The principal value of `sin^-1 [cos(sin^-1  1/2)]` is `pi/3`.

विकल्प

• True

• False

Answer 1

This statement is True.

Explanation:

`sin^-1 [cos(sin^-1  1/2)] = sin^-1 [cos(sin^-1  sin  pi/6)]`

`sin^-1 [cos  pi/6] = sin^-1  (sqrt(3)/2)`

= `sin^-1 (sin  pi/3)`

= `pi/3`