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प्रश्न
The potential energy of a particle under a conservative force field is given by U = 10 + (x - 4)2, where x is in meters. At x = 6 m, the K.E. of the particle is 10 J. The maximum kinetic energy of the particle is ______ J.
विकल्प
11.00
12.00
13.00
14.00
MCQ
रिक्त स्थान भरें
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उत्तर
The potential energy of a particle under a conservative force field is given by U = 10 + (x - 4)2, where x is in meters. At x = 6 m, the K.E. of the particle is 10 J. The maximum kinetic energy of the particle is 14.00 J.
Explanation:
When KE = 10 J
U = 10 + (6 - 4)2 = 14 J
TME = KE + PE
= (10 + 14) J = 24 J
When KE is maximum PE is minimum.
TME = KEmax + PEmin
24 = KEmax + 10
KEmax = 14 J
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