हिंदी

The potential energy of a particle under a conservative force field is given by U = 10 + (x - 4)2, where x is in meters. At x = 6 m, the K.E. of the particle is 10 J. The maximum kinetic energy

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प्रश्न

The potential energy of a particle under a conservative force field is given by U = 10 + (x - 4)2, where x is in meters. At x = 6 m, the K.E. of the particle is 10 J. The maximum kinetic energy of the particle is ______ J.

विकल्प

  • 11.00

  • 12.00

  • 13.00

  • 14.00

MCQ
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उत्तर

The potential energy of a particle under a conservative force field is given by U = 10 + (x - 4)2, where x is in meters. At x = 6 m, the K.E. of the particle is 10 J. The maximum kinetic energy of the particle is 14.00 J.

Explanation:

When KE = 10 J

U = 10 + (6 - 4)2 = 14 J

TME = KE + PE

= (10 + 14) J = 24 J

When KE is maximum PE is minimum.

TME = KEmax + PEmin

24 = KEmax + 10

KEmax = 14 J

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