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प्रश्न
The plot of log k vs X is linear with a slope = `(-E_a)/(2.303 R)`. What is X?
संख्यात्मक
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उत्तर
The variable X in the expression
slope = `(-E_a)/(2.303 R)`
comes from the Arrhenius equation in its logarithmic form
`log k = log A - E_a/(2.303 RT)`
This equation is linear in the form
`log k = -E_a/(2.303 RT) * 1/T + log A`
This is of the form y = mx + cy, where
logk is plotted on the y-axis,
`1/T` is plotted on the x-axis (with temperature T in Kelvin),
slope = `-E_a/(2.303 R)`
∴ `X = 1/T`
So, the plot of log k vs `1/T` is linear with slope `-E_a/(2.303 R)`
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