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प्रश्न
The p.d.f. of a random variable X is given by :
f(x) = 2x, 0 ≤ x ≤ 1
= 0, otherwise
Find `P(1/3 < x < 1/2)`
योग
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उत्तर
`p(1/3 < x < 1/2) = int_(1/2)^(1/3) f(x) dx`
= `int_(1/3)^(1/2) 2x dx`
= `[ 2(x^2/2)]_(1/3)^(1/2) = [(x^2)]_(1/3)^(1/2)`
= `(1/2)^2 - (1/3)^2`
= `1/4 - 1/9`
= `5/36`
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