Question

The pair of complexes wherein both exhibit tetrahedral geometry is (are): (Note: Py = Pyridine)

(Given atomic numbers of Fe, CO, Ni and Cu are 26, 27, 28 and 29 respectively.)

विकल्प

• [FeCl₄]⁻ and [Fe(CO)4]²⁻

• [Co(CO)₄]⁻ and [CoCl₄]²⁻

• [Ni(CO)₄] and [Ni(CN)₄]²⁻

• [Cu(Py)₄]⁺ and [Cu(CN)₄]³⁻

Answer 1

[FeCl₄]⁻ and [Fe(CO)4]²⁻, [Co(CO)₄]⁻ and [CoCl₄]²⁻, [Cu(Py)₄]⁺ and [Cu(CN)₄]³⁻

Explanation:

• [FeCl₄]⁻ and [Fe(CO)₄]²⁻:  In [FeCl₄]⁻ iron (Fe, atomic number 26) in +3 oxidation state and in Fe(CO)₄]²⁻ iron (Fe, atomic number 26) in +2 oxidation state. Both exhibit tetrahedral geometry because they have four ligands (Cl⁻ or CO) around the central metal ion.
• [Co(CO)₄]⁻ and [CoCl₄]²⁻: In [Co(CO)₄]⁻ cobalt (Co, atomic number 27) in +1 oxidation state and in [CoCl₄]²⁻  cobalt (Co, atomic number 27) in +2 oxidation state. Both also exhibit tetrahedral geometry due to the four coordinating ligands around the central metal.
• [Ni(CO)₄] and [Ni(CN)₄]²⁻: In [Ni(CO)₄] nickel (Ni, atomic number 28) in the 0 oxidation state and tetrahedral, but [Ni(CN)₄]²⁻ nickel (Ni, atomic number 28) in +2 oxidation state and square planar geometry.
• [Cu(Py)₄]⁺ and [Cu(CN)₄]³⁻: In [Cu(Py)₄]⁺  Copper (Cu, atomic number 29) in +1 oxidation state and [Cu(CN)₄]³⁻ opper (Cu, atomic number 29) in +3 oxidation state. Both adopt tetrahedral geometry.

Thus, the pairs with tetrahedral geometry are [FeCl₄]⁻ and [Fe(CO)₄]²⁻, [Co(CO)₄]⁻ and [CoCl₄]²⁻, [Cu(Py)₄]⁺ and [Cu(CN)₄]³⁻.