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प्रश्न
The one that can exhibit highest paramagnetic behaviour among the following is:
विकल्प
[Fe(en)(bpy)(NH3)2]2+
[Pd(gly)2]
[Ti(NH3)6]3+
[Co(ox)2(OH)2]− (Δo > P)
MCQ
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उत्तर
[Co(ox)2(OH)2]− (Δo > P)
Explanation:
- [Co(ox)2(OH)2]− is Co3+ has a 3d6 configuration. With weak field ligands like oxalate (ox) and hydroxide (OH), it remains in a high-spin state, resulting in 4 unpaired electrons. This leads to strong paramagnetic behaviour. Additionally, the high-spin nature of this complex is favoured by the condition Δo > P, which means the crystal field splitting energy (Δo) is greater than the pairing energy (P), allowing for more unpaired electrons.
- The other complexes have fewer unpaired electrons, resulting in weaker paramagnetic behaviour.
Thus, [Co(ox)2(OH)2]− exhibits the highest paramagnetic behaviour.
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