Advertisements
Advertisements
प्रश्न
The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Advertisements
उत्तर
Initial reading of the odometer of the car = 57321.0 km
The final reading of the odometer of the car = 57336.0 km
Distance covered by the car
= Final reading of the odometer of the car - Initial reading of the odometer of the car
= 57336.0 - 57321.0
= 15 km
The given car starts at 8:30 a.m. and stops at 8:50 a.m.
Therefore, the time taken by the car to cover the distance is (8:50 − 8:30) min = 20 min
Distance covered by the car = 15 km
Time taken by the car = 20 min
Speed = `"Distance covered"/"Time taken" `
= `15/20`
= 0.75 km/min
Again
60 min = 1 h
20 min = `1/60 xx 20`
= `1/3` h
Time taken by the car = `1/3` h
Speed = `"Distance covered"/"Time Taken"`
= `15/(1/3)`
= 45 km/h.
APPEARS IN
संबंधित प्रश्न
A simple pendulum takes 32 s to complete 20 oscillations. What is the time period of the pendulum?
Suppose the two photographs, shown in Figure 1 and Figure 2, had been taken at an interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs, calculate the speed of the fastest car.
Figure 1 Vehicles moving in the same direction on a road
Figure 2 Position of vehicles shown in Figure 1 after some time
For a body moving along a circular path, show that:
Linear speed = Angular velocity X radius of the circle
A car travels 30 km at a uniform speed of 60 km/h and the next 30 km at a uniform speed of 20 km/h. What is its average speed?
The correct relation among the following is
A vehicle covers a distance of 400km in 5 hours. Calculate its speed.
The time period of a given pendulum is constant.
The speed of a train is expressed in m/h.
Define speed Mention its formula and unit.
Which of the quantities have the same SI unit?
